write anything here. blah blah blah.
Friday, March 10, 2006
Guess what my brother has been lying about his test results :( and he's hiding alot of things.
So my mom told me to find out more of what he's doing secretly.
Aha it's really fun. For example the geniooos left his msn password on the msn sign in page so i simply signed in! And then i secretly changed his mesasge saving options htingy so that his conversations will be saved and i'll be able to read them. FUN!!
Later on i tried to guess the names of his friends/classmates through their email but there were too many of those stupid ones like AUTUM_DREAM and SKY_GURL. mmm =/
typos are so KOOL.
In the end i couldnt' find out the names of some of his friends so i decided to go into his hotmail inbox which has 393 unread messages. thats like about 150+ more than mine bleh. So i saw his list of contacts in there and the sender's names. I DESERVEZ TO WIN TEH NOBEL PRIZE LARHZ WALAO KNN CC****************************************.
Now all i have to do is let my brother use the comp more often so that i'll have some chat logs to read. i think it's going to be rather gross reading my brother's chatlogs, probably with all the smileys =) =D =( ^.^ 8_8 0.0 ><>The predicted variation of detected alphas with angle is followed closely by the Geiger-Marsden data. The above form includes the cross-section for scattering for a given nucleus and the nature of the scattering film to get the scattered fraction. Another common form for the Rutherford equation is just the differential cross section for scattering from a given nucleus. Assigning priorities for double bonds becomes a bit more challenging (this applies in the same fashion to carbonyls, C=O, and imines, C=N). A carbon with a double bond to another carbon is treated as a carbon singly bonded to two carbons, as shown below. This means that, for example, an ethylene substituent, R-CH=CH2, will have a higher priority then an ethyl substituent (R-CH2CH3). If you add 1 to f(x), this will shift the graph up 1 unit. Similarly, f(x) + n shifts the graph upwards by n units. f(x - 1), in other words replacing all the x's in the formula with (x - 1), will cause the graph to shift 1 unit to the right. So f(x - n) shifts the graph n units to the right. Similarly, f(x + n) shifts the whole graph n units to the left. Lichens are a symbiosis between a photosynthetic organism (alga or cyanobacterium) and a fungus (sac or club). Mycorrhizae are fungi (usually a zygomycete or basidiomycete) symbiotic with the roots of plants. Both relationships are mutualistic: both parties benefit. Fungi provide nutrients from the substrate, the phototroph provides food. Plants with mycorrhizae grow better: the plant gets nutrients from the fungus in exchange for carbohydrates.
school
happy holidays :)
autumn, yet winter started on 8:22 PM